Last Updated On : 20-May-2026


Salesforce Certified JavaScript Developer - JS-Dev-101 Practice Test

Prepare with our free Salesforce Certified JavaScript Developer - JS-Dev-101 sample questions and pass with confidence. Our Salesforce-JavaScript-Developer practice test is designed to help you succeed on exam day.

221 Questions
Salesforce 2026

A developer has an ErrorHandler module that contains multiple functions. What kind of export should be leveraged so that multiple functions can be used?

A. all

B. named

C. multi

D. default

B.   named

Refer to the following code:

 


A

After user acceptance testing, the developer is asked to change the webpage background based on user's location. This change was implemented and deployed for testing.
The tester reports that the background is not changing, however it works as required when viewing on the developer's computer.
Which two actions will help determine accurate results?
Choose 2 answers

A. The developer should inspect their browser refresh settings.

B. The tester should disable their browser cache.

C. The developer should rework the code.

D. The tester should dear their browser cache.

A.   The developer should inspect their browser refresh settings.
D.   The tester should dear their browser cache.

Refer to code below:
Function muFunction(reassign){
Let x = 1;
var y = 1;
if( reassign ) {
Let x= 2;
Var y = 2;
console.log(x);
console.log(y);}
console.log(x);
console.log(y);}
What is displayed when myFunction(true) is called?

A. 2 2 1 1

B. 2 2 undefined undefined

C. 2 2 1 2

D. 2 2 2 2

C.   2 2 1 2

Explanation:

This question tests your understanding of variable scoping in JavaScript, specifically the difference between let and var.
Inside the if Block (reassign is true):
let x = 2; creates a new, block-scoped variable x. This variable is separate from the x declared outside the if block. When console.log(x); is called, it accesses this new block-scoped x, which has a value of 2.
var y = 2; re-declares the variable y. Because var is function-scoped, this declaration simply overwrites the value of the y declared outside the if block. When console.log(y); is called inside the if block, it logs the new value, which is 2.

So, the first two console.log statements display 2 and 2.

Outside the if Block:
The first console.log(x); is outside the if block. It references the original x declared with let at the beginning of the function. This variable was not affected by the let x = 2 declaration inside the if block. Therefore, it logs the original value, which is 1.
The second console.log(y); is also outside the if block. Since the var y = 2 declaration inside the if block affected the function-scoped y, this y now holds the value 2. Therefore, it logs 2.

Combining these results, the output is 2 2 1 2.

Refer to the code below:

What is the result when the Promise in the execute function is rejected?

A. Resolved1 Resolved2 Resolved3 Resolved4

B. Rejected

C. Rejected Resolved

D. Rejected1 Rejected2 Rejected3 Rejected Rejected Rejected4

C.   Rejected Resolved
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